(x2 - 2x)(x3 - 3x2 - 18x) = 0
\(\Rightarrow\orbr{\begin{cases}x^2-2x=0\\x^3-3x^2-18x=0\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}x+x-2x=0\\x+x+x-3x+x-18x=0\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}x\left(1+1-2\right)=0\\x\left(1+1+1-3+1-18\right)=0\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}x=0\\x\left(-17\right)=0\end{cases}}\)
\(\Rightarrow x=0\)
vậy \(x=0\)
vì (x2-2x) (x3-3x2-18x) = 0
=>hoặc x3-3x2-18x=0
TH1: x2-2x=0
=>x(x-2)=0
=> x-2=0 =>
=>x=2
TH2: tương tự
\(\left(x^2-2x\right)\left(x^3-3x^2-18x\right)=0\)
\(\Leftrightarrow\)\(x\left(x-2\right)x\left(x^2-3x-18\right)=0\)
\(\Leftrightarrow\)\(x^2\left(x-2\right)\left(x^2-6x+3x-18\right)=0\)
\(\Leftrightarrow\)\(x^2\left(x-2\right)\left(x-6\right)\left(x+3\right)=0\)
\(\Leftrightarrow\)\(x=0;\)\(x=2;\)\(x=6;\)\(x=-3\)