Question

\(^{x^2-2=\frac{1}{4}}\)^{\(-\frac{3}{2}.\left(\frac{4}{5}+x\right)=1\frac{3}{2}\)}giúp mình nhanh nhé cần gấp ai trước èn đúng tôi tích cho

Answer 1

1.....

2....

3.Ok 

Answer 2

a) \(x^2-2=\frac{1}{4}\)

\(\Rightarrow x^2=\frac{1}{4}+2\)

\(\Rightarrow x^2=\frac{9}{4}=2,25=1,5^2\)

\(\Rightarrow x=1,5\)

b) \(-\frac{3}{2}.\left(\frac{4}{5}+x\right)=1\frac{3}{2}\)

\(\Rightarrow-\frac{3}{2}.\left(\frac{4}{5}+x\right)=\frac{5}{2}\)

\(\Rightarrow\frac{4}{5}+x=\frac{5}{2}:-\frac{3}{2}\)

\(\Rightarrow\frac{4}{5}+x=-\frac{5}{3}\)

\(\Rightarrow x=-\frac{5}{3}-\frac{4}{5}\)

\(\Rightarrow x=-\frac{37}{15}\)