Question

x^2-2015x+2014=0 hãy tìm x

Answer 1

<=>(x²-x)-(2015x-2014)=0

<=>x(x-1)-2014(x-1)=0

<=>(x-2014)(x-1)

<=>x-2014=0

hoặc x-1=0

<=>x=2014

hoặc x=1

h

Answer 2

\(x^2-2015x+2014=0\)

\(\Leftrightarrow x^2-2014x-x+2014=0\)

\(\Leftrightarrow x\left(x-2014\right)-\left(x-2014\right)=0\)

\(\Leftrightarrow\left(x-1\right)\left(x-2014\right)=0\)

\(\Leftrightarrow\orbr{\begin{cases}x-1=0\\x-2014=0\end{cases}}\Leftrightarrow\orbr{\begin{cases}x=1\\x=2014\end{cases}}\)