Question

(x+1)+(x+2)+(x+3)+...+x+100=7150

Answer 1

(x+1)+(x+2)+............+(x+100)=7150

=>x+1+x+2+..............+x+100=7150

=>100x+(1+2+3+..............+100)=7150

=>100x+5050=7150

=>100x=7150-5050

=>100x=2100

=>x=2100:100

=>x=21

Answer 2

(x+1)+(x+2)+(x+3)+...+(x+100)=5750 
x + 1 + x + 2 + x + 3 + .... + x + 100 = 5750 
(x + x + x + ... + x) + (1 + 2 + 3 + ... + 100) = 5750 
100x + 5050 = 5750 
100x = 5750 - 5050 = 700 
x = 700 : 100 = 7

Đề sai phải là 5750 mới đúng

Answer 3

21 nhé bạn

duyệt đi

Answer 4

x = 21 

chúc Mai học giỏi nha

Answer 5

<=> ( x + x + x + .... + x ) + ( 1 + 2 + 3 + .... + 100 ) = 7150

<=> ( 100x ) + [ 100.( 100 + 1 ) : 2 ] = 7150

<=> 100x + 5050 = 7150

<=> 100x = 7150 - 5050

<=> 100x = 2100

<=> x = 2100 : 100

=> x = 21

Answer 6

(x+1)+(x+2)+(x+3)+....+x+100=7150

= 100x + (1+2+3+4+...+100)=7150

=100x + 5050 = 7150

100x = 7150-5050

100x = 2100   .  vậy x = 2100/100 = 21