Question

(x+1)(x+2)-(x+1)(x-6)=0

Answer 1

(x+1)(x+2)-(x+1)(x-6)=0

=> (x²+2x+x+2)--(x²--6x+x-6)=0

=> x²+3x+2--x²+7x+6=0

=>10x+8=0

=>10x=8

=>x=\(\frac{8}{10}=\frac{4}{5}\)

Answer 2

(x + 1)(x + 2) - (x + 1)(x - 6) = 0

=> (x + 1)(x + 2 - x + 6) = 0

=> (x + 1).8 = 0

=> x + 1 = 0

=> x = -1 .Vậy x = -1