Question

(X+1)(x-4)=3x-4

Answer 1

\(\left(x+1\right)\left(x-4\right)=3x-4\Leftrightarrow x^2-4x+x-4=3x-4\Leftrightarrow x^2-3x-4=3x-4\)

\(\Leftrightarrow x^2-3x-4-\left(3x-4\right)=0\Leftrightarrow x^2-3x-4-3x+4=0\Leftrightarrow x^2-6x=0\Leftrightarrow x\left(x-6\right)=0\Leftrightarrow x=0;x=6\)

Vậy giá trị x cần tìm là x=0 và x=6

Answer 2

(x+1)(x-4)=x^2-4x+x-4=3x-4

x^2-3x-4=3x-4

x^2-3x-4-3x+4=0

x^2-6x=0

x(x-6)=0

x=0 hoac x-6=0

x=0 hoac x=6

Answer 3

(x+1)(x-4)=3x-4

x²-4x+x-4=3x-4

x²-3x-4=3x-4

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