sửa đề tí nhé: \(x=\frac{1}{3.5}+\frac{1}{5.7}+\frac{1}{7.9}+...+\frac{1}{197.199}\)
\(x=\frac{1}{2}.\left(\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{7}+\frac{1}{7}-\frac{1}{9}+...+\frac{1}{197}-\frac{1}{199}\right)\)
\(x=\frac{1}{2}.\left(\frac{1}{3}-\frac{1}{199}\right)\)
\(x=\frac{1}{2}.\frac{196}{597}\)
\(x=\frac{98}{597}\)
Mình lấy \(\frac{1}{5-3}=\frac{1}{2}\) :D