\(\left(x+\frac{1}{2}\right)^2=\frac{1}{16}\)
\(\left(x+\frac{1}{2}\right)^2=\left(\frac{1}{4}\right)^2\)
=>\(x+\frac{1}{2}=\frac{1}{4}\)
\(x=\frac{-1}{4}\)
1+1/2 x (1+2) + 1/3 x (1+2+3) + ...........+ 1/16 x (1+2+3+......16) = ?
1. ( x + 1/2 )^2 = 1/16
2.( x-1/2)^2=16
Tìm x biết
( x + 1/2 )^2 -1/16 =0
( 3x + 1/2 )^2 + 25/16 = 0
\(\frac{1}{1-x}+\frac{1}{1+x}+\frac{2}{1+x^2}+\frac{4}{1+x^4}+\frac{8}{1+x^8}+\frac{16}{1+x^{16}}\)
Ta có: 4x=5y => x/5=y/4=>x2/25=y2/16
ta có:
x2/25=y2/16=x2-y2/25-16=1/9
x^2/25=1/9=>x^2=25/9=>x=5/3
y^2/16=1/9=>y^2=16/9=>y=4/3
tích của chúng bằng:5/3*4/3=20/9
tìm x biết (1/1*101+1/2*102+...+1/16*116)*x=1/1*11+1/2*12+...+1/16*26
A, thực hiện phép tính
M=1+1/2(1+2)+1/3(1+2+3)+1/4(1+2+3+4)+...+1/16(1+2+3+4+...+16)
B, tìm x biết
|4x+3|-|x-1|=7
1)x/27=-2/36
2)(x+1/2)^2=1/16
TÌM X
câu 1: (1/3 + 1/6) . 2^x+3 - 2^x = 2^22 - 2^20
câu 2: (1/2-1/6).3^x+3^x+2=3^16+3^13
câu 3: (1/2 - 1/6) . 3^x+4 - 4 . 3^x = 3^16 - 4 . 3^13
mình cần gấp. mn lm ơn giúp mifh vs ạ. !!!huhuhu
