\(\left(x+1\right)^2-\left(2-x\right)^2=4\)
\(\Leftrightarrow\left(x+1+2-x\right)\left(x+1-2+x\right)=4\)
\(\Leftrightarrow3\left(2x-1\right)=4\)
\(\Leftrightarrow2x-1=\frac{4}{3}\)
\(\Leftrightarrow2x=\frac{7}{3}\)
\(\Leftrightarrow x=\frac{7}{3}:2=\frac{7}{6}\)
x2 + 2x + 1 - 4 + 4x - x2 = 4
<=> 6x = 7
<=> x = \(\frac{7}{6}\)