Ta có: \(\frac{x+1}{15}+\frac{x+2}{16}+\frac{x+3}{17}=3\)
=> \(\left(\frac{x+1}{15}-1\right)+\left(\frac{x+2}{16}-1\right)+\left(\frac{x+3}{17}-1\right)=0\)
=> \(\frac{x-14}{15}+\frac{x-14}{16}+\frac{x-14}{17}=0\)
=> \(\left(x-14\right)\left(\frac{1}{15}+\frac{1}{16}+\frac{1}{17}\right)=0\)
=> \(x-14=0\)
=> \(x=14\)