Đặt : \(\frac{x}{10}=\frac{y}{7}=k\)
\(\Rightarrow\frac{x}{10}=k\)
\(\Rightarrow\frac{y}{7}=k\)
\(\Rightarrow x=10k;y=7k\)
Ta có : \(10k.7k=280\)
\(70k^2=280\)
\(k^2=4\)
\(\Leftrightarrow\orbr{\begin{cases}k=2\\k=-2\end{cases}}\)
TH1 : \(k=2\)
\(\frac{x}{10}=2\Rightarrow x=20\)
\(\frac{y}{7}=2\Rightarrow y=14\)
TH2 : \(k=-2\)
\(\frac{x}{10}=-2\Rightarrow x=-20\)
\(\frac{y}{7}=-2\Rightarrow y=-14\)
Vậy ..........................
\(\frac{x}{10}=\frac{y}{7}=\frac{x.y}{10.7}=\frac{280}{70}=4\)
\(\Rightarrow x=4.10=40\)
\(y=4.7=28\)
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