1,tìm x,y:
\(\left|x-y\right|+\left|y+\frac{9}{25}\right|=0\)
tìm x , y\(\left|\frac{1}{2}-\frac{1}{3}+x\right|=-\frac{1}{4}-\left|y\right|\)
\(\left|x-y\right|+\left|y+\frac{9}{25}\right|=0\)
Cho \(\frac{x+16}{9}=\frac{y-25}{16}=\frac{z+9}{25}\)và\(\frac{9-x}{7}+\frac{11-x}{9}=2\)
Tìm x,y,z
Cho \(A=\frac{x+16}{9}=\frac{y-25}{16}=\frac{z+9}{25}\) và \(\frac{9-x}{7}+\frac{11-x}{9}=2\)
tìm x+y+z
Tìm x,y,z biết:
Cho \(\frac{x+16}{9}=\frac{y-25}{16}=\frac{z+9}{25}và2x^2-1=15\)
Cho \(\frac{x+16}{9}\)=\(\frac{y-25}{16}\)=\(\frac{z+9}{25}\)và \(\frac{9-x}{7}\)+\(\frac{11-x}{9}\)= 2.Tìm x+y+z.
|x-y|+|y+\(\frac{9}{25}\)|=0
Cho \(\frac{x+16}{9}=\frac{y-25}{16}=\frac{z+9}{25}\) và \(2x^3-1=15\)
Tìm x,y,z.
Cho \(\frac{x+16}{9}=\frac{y-25}{16}=\frac{z+9}{25}\) và \(2x^3-1=15.\)Tìm \(x+y+z\)