\(\left(x-\frac{1}{2}\right)^2=0\)
\(\Rightarrow x-\frac{1}{2}=0\Rightarrow x=\frac{1}{2}\)
(x-1/2)2=0
=>x-1/2=0
=>x=0+1/2
=>x=1/2
1. Tính nhanh
a) x.(x-2)=0
b) \(\left(\frac{1}{2}+\frac{2}{3}-\frac{1}{4}\right).\left(X-3\right)=0\)
c) (X-10).(X-20)=0
d) (x-2).(x^2-1)=0
e) 2|4-x|=|-8|
!.TÌm x, biết
a) x.(x-2)=0
b) \(\left(\frac{1}{2}+\frac{2}{3}-\frac{1}{4}\right).\left(X-3\right)=0\)
c) (X-10).(X-20)=0
d) (x-2).(x^2-1)=0
e) 2|4-x|=|-8|
1 tìm x biết ;
a, 0-|x + 1| = 5
b, 2 - | \(\frac{3}{4}\)- x | = \(\frac{7}{12}\)
c, 2 | \(\frac{1}{2}\)x - \(\frac{1}{3}\)| - \(\frac{3}{2}\)= \(\frac{1}{4}\)
d, | x - \(\frac{1}{3}\)| = \(\frac{5}{6}\)
e, \(\frac{3}{4}\)- 2 | 2x - \(\frac{2}{3}\)| = 2
f, \(\frac{2x-1}{2}\)= \(\frac{5+3x}{3}\)
1 tìm x biết ;
a, 0-|x + 1| = 5
b, 2 - | \(\frac{3}{4}\)- x | = \(\frac{7}{12}\)
c, 2 | \(\frac{1}{2}\)x - \(\frac{1}{3}\)| - \(\frac{3}{2}\)= \(\frac{1}{4}\)
d, | x - \(\frac{1}{3}\)| = \(\frac{5}{6}\)
e, \(\frac{3}{4}\)- 2 | 2x - \(\frac{2}{3}\)| = 2
f, \(\frac{2x-1}{2}\)= \(\frac{5+3x}{3}\)
Giải: a) \(\frac{x+2}{x+1}=\frac{4x^2-11x-2}{x^2+x-2}\)
b) \(\frac{1}{2}x^4-\frac{1}{3}x^2-\frac{1}{6}=0\)
\(a)\frac{2}{5}:(2x+\frac{3}{4})=\frac{-7}{10}\)
\(b)\frac{x+1}{3}=\frac{2-x}{2}\)
\(c)|x-\frac{3}{5}|.\frac{1}{2}-\frac{1}{5}=0\)
\(^{d)x^2-4x=0}\)
Tìm x giúp mình nha!!!
\(\frac{X-1}{x+2}>0\)A,\(\frac{X-2}{4}=\frac{-9}{2-x}\)và x>y
B,\(\frac{\left(x-1\right)^2}{6}=\frac{-8}{-12}=\frac{10}{7-y}=\frac{7z}{-21}\)
C,\(\frac{X}{15}=\frac{3}{y}\)và x<y<0
D,\(\frac{X}{4}=\frac{y}{3}\)và x+y=14
e,\(\frac{X+1}{x-2}< 0\)
G,
tìm x :
a)\(x:4\frac{1}{3}=2.5\)
b)\(x:\frac{-3}{5}=\frac{-10}{21}\)
c)\(\frac{2}{3}.x-\frac{1}{2}=\frac{1}{10}\)
d)\(\frac{1}{3}.x+\frac{2}{5}\left(x-1\right)=0\)
e)\(\frac{1}{2}.x+\frac{1}{2}=\frac{5}{2}\)
f)\(\frac{-2}{3}-\frac{1}{3}\left(2x-5\right)=\frac{3}{2}\)
g)\(\left(3x-1\right)\left(-\frac{1}{2}.x+5\right)=0\)
h)\(3\frac{1}{3}+\frac{5}{6}.x=3\frac{1}{2}\)
Tìm x
\(\left(2x+\frac{3}{5}\right)^2-\frac{9}{25}=0\)
\(3\left(3x-\frac{1}{2}\right)^3+\frac{1}{9}=0\)
\(-5\left(x+\frac{1}{5}\right)-\frac{1}{2}\left(x-\frac{2}{3}\right)=\frac{3}{2}x-\frac{5}{6}\)
\(3\left(x-\frac{1}{2}\right)-5\left(x+\frac{3}{5}\right)=-x+\frac{1}{5}\)
giải nhanh hộ mình với, mai mình nộp rồi
2(x-\(\frac{1}{2}\))+3 (-1+\(\frac{x}{3}\))=x(\(\frac{2}{x}\)- 1) (x#0)
