a, \(\left|x+9\right|=12+\left(-9\right)+2\)
\(\Leftrightarrow\left|x+9\right|=12-9+2=5\Leftrightarrow\left|x+9\right|=\pm5\)
TH1 : \(x+9=5\Leftrightarrow x=-4\)
TH2 : \(x+9=-5\Leftrightarrow x=-14\)
b, \(5x-16=40+x\Leftrightarrow4x=56\Leftrightarrow x=14\)
c, \(5x-7=-21-2x\Leftrightarrow7x=-14\Leftrightarrow x=-2\)
| x + 9 | = 12 + ( - 9 ) + 2
| x + 9 | = 3+2
| x + 9 | = 5
TH1: x+9 = 5 TH2: x+9 = -5
=>x=-4 =>x=-14
Vậy x {-4;-14}
5x - 16 = 40 + x
5x - 16 = 40 + 1x
=>5x-1x = 40+16
4x = 56
=> x = 14
5x - 7 = - 21 - 2x
=> 5x - 2x = -21 - 7
3x = -28
=> x = -9,(3)