Question

X-6-(48-24×2÷6-3)=100

20-[7×(X-3)+4]=2

[(6×X-39)÷3].28=5628

 

Answer 1

x-6-(48-24x2:6-3)=100

x-6-(48-8-3)=100

x-6-37=100

x-6=137

x=137+6=143

Vậy x=143

20-[7x(X-3)+4]=2

7x(X-3)+4=20-2

7x(X-3)+4=18

7x(X-3)=14

X-3=14:7

X-3=7

X=7+3=10

Vậy X=10

[(6.X-39):3].28=5628

(6.X-39):3=5628:28

(6.X-39):3=201

6.X-39=201.3=603

6.X=603+39

6.X=642

X=642:6=107

Vậy x=107

Answer 2

1)  \(x-6-\left(48-24.2:6-3\right)=100\Rightarrow x-6-\left(48-8-3\right)=100\)

\(\Rightarrow x-6-37=100\Rightarrow x=100+37+6=143\)

2)  \(20-\left[7\left(x-3\right)+4\right]=2\Rightarrow7\left(x-3\right)+4=20-2=18\)

\(\Rightarrow7\left(x-3\right)=18-4=14\Rightarrow x-3=14:7=2\Rightarrow x=2+3=5\)

3)   \(\left[\left(6x-39\right):3\right].28=5628\Rightarrow\left(6x-39\right):3=5628:28=201\)

\(\Rightarrow6x-39=201.3=603\Rightarrow6x=603+39=642\Rightarrow x=642:6=107\)