[(x+50) . 50 - 50] : 50 = 50
[(x+50) . 50 - 50] = 50.50
[(x+50) . 50 - 50] = 100
(x+50) . 50 = 100+50
(x+50) . 50 = 150
(x+50) = 150 : 50
x+50 = 3
x = 3 - 50
x = -47
[(x + 50) . 50 - 50] : 50 = 50
[(x + 50) . 50 - 50] = 50 . 50
(x + 50) .50 - 50 = 250
(x + 50) . 50 = 250 + 50
(x + 50) . 50 = 300
x + 50 = 300 : 50
x + 50 = 6
x = 6 - 50
x = -44
Xin lỗi, mình nhầm:
[ ( x + 50) . 50 - 50 ] : 50 = 50
[ ( x + 50) . 50 - 50 ] = 50 . 50
[ ( x + 50) . 50 - 50 ] = 2500
( x + 50) . 50 = 2500+50
( x + 50) . 50 = 2550
( x + 50) = 2550 : 50
x + 50 = 51
x = 51 - 50
x = 1
\(\left[\left(x+50\right).50-50\right]:50=50\)
\(\left(x+50\right).50-50=50.50\)
\(\left(x+50\right).50-50=2500\)
\(\left(x+50\right).50=2500+50\)
\(\left(x+50\right).50=2550\)
\(x+50=2550:50\)
\(x+50=51\)
\(x=51-50\)
\(x=1\)
Chúc bạn học tốt!
Thân!
\(\left[\left(x+50\right)\cdot50-50\right]:50=50\)
\(\left(x+50\right)\cdot50-50=50\cdot50\)
\(\left(x+50\right)\cdot50=50\cdot50-50\)
\(\left(x+50\right)\cdot50=50\left(50-1\right)\)
\(\Rightarrow x+50=49\)
\(x=49-50\)
\(x=-2\)
thank kiu tất cả các bạn nha . Mình được 1 điểm câu đó rồi !
