Ta có : \(\left(x-5\right).\left(x-3\right)=0\)
\(\Leftrightarrow x-5=0\) hoặc \(x-3=0\)
\(\left(+\right)x-5=0\Leftrightarrow x=5\)
\(\left(+\right)x-3=0\Leftrightarrow x=3\)
Vậy \(x=5;x=3\)
(x-5).(x-3)=0
=>x-5=0 hoặc x-3=0
+)Nếu x-5=0
=>x=0+5=5
+)Nếu x-3=0
=>x=0+3=3
Vậy x=5 hoặc x=3
\(\left(x-5\right)\cdot\left(x-3\right)=0\)
x - 5 = 0
x = 5
x - 3 = 0
x = 3
\(x\hept{\begin{cases}5\\3\end{cases}}\)
( x - 5 ) . ( x - 3 ) = 0
x - 5 = 0 ; x - 3 = 0
=> x = 5 + 0 ; x = 3 + 0
=> x = 5 ; x = 3
(x-5)+(x-3)=0
=> x-5=0 hoac x-3=0
x=0+5 x=0+3
x=5 x=3
Zay x=5 hoac x=3
Nho click cho mk nha
(x-5).(x-3)=0
x-5=0;x-3=0
Suy ra x=5+0;x=3+0
Vậy x=5 hoặc x=3.
( x - 5 ) . ( x - 3 ) = 0
x - 5 = 0 ; x - 3 = 0
=> x = 5 + 0 ; x = 3 + 0
=> x = 5 ; x = 3
\(\text{Ta có: ( x - 5 ) . ( x - 3 ) = 0}\)
\(\Leftrightarrow\orbr{\begin{cases}x-5=0\\x-3=0\end{cases}}\)
\(\Leftrightarrow\orbr{\begin{cases}x=0+5\\x=0+3\end{cases}}\)
\(\Leftrightarrow\orbr{\begin{cases}x=5\\x=3\end{cases}}\)
