tim x;y thuoc Z: (x-3)(2y+1)=7
Tim x,y thuoc Z
(x-3).(2y+1)=7
Tìm x, y thuoc Z
a, ( x +1 ) ( y - 2 ) = 3
b, ( 1 - x ) ( 2y - 1 ) =4
tim x,y thuoc Z biet
|y|.|2x+3|=8
|2x+4|+|y-3|=0
|x-1|+|2y+7|=3
|x+5|+|2y+6| nho hon hoac bang 0
Tim x,y thuoc Z biet
a}[x-3].[2y+1]=7
b}[2x+1].[3y-2]=-55
tim x, y thuoc z biet xy-x+2y=3
tim x,y thuoc z sao cho:
7x-xy+2y=18
Cau 1 .Cho A = 3/4 + 8/9 + 15/16 +…+ 9999/10000
Chung to a lon hon 4/3
CAU 2 . A = x/x+y + y/y+z +x/x+z
Cho z , y z thuoc N* chung to A k thuoc N
Tim x;y thuoc N biet (x-1)(2y+3)=26