Question

( x-3 ) ^x+2 - (x-3)^x+8 = 0 

cứu mk nha chiều mai nộp r

Answer 1

Ý bạn là mũ x hay là mũ x+2 ( x+8) vậy?

Answer 2

\(\left(x-3\right)^x+2-\left(x-3\right)^x+8=0\)

\(\Leftrightarrow\left(x-3\right)^x\cdot\left(2+8\right)=0\)

\(\Leftrightarrow10\cdot\left(x-3\right)^x=0\)

\(\Leftrightarrow\left(x-3\right)^x=0\)

\(\Leftrightarrow x-3=0\)

\(\Leftrightarrow x=3\)