\(\left(x-\frac{2}{9}\right)^3=\left(\frac{2}{3}\right)^6\Rightarrow\left(x-\frac{2}{9}\right)^3=\left[\left(\frac{2}{3}\right)^2\right]^3\)
\(\Rightarrow\left(x-\frac{2}{9}\right)^3=\left(\frac{4}{9}\right)^3\)
\(\Rightarrow x-\frac{2}{9}=\frac{4}{9}\Rightarrow x=\frac{2}{3}\)
Vậy x = 2/3