Question

(x-2)⁶=(x-2)⁸

Tim so tu nhien x biet

 

Answer 1

(x-2)^6-(x-2)^8=0

(x-2)^6[1-(x-2)^2]=0

+) (x-2)^6=0

=>x-2=0

x=2

+) 1-(x-2)^2=0

(x-2)^2=1

+) x-2=1            +) x-2=-1

=>x=3                        x=1

Answer 2

(x - 2)⁶ = (x - 2)⁸ 

<=> (x - 2)⁸ - (x - 2)⁶ = 0

<=> (x - 2)⁶(x - 2)² - (x - 2)⁶ = 0

<=> (x - 2)⁶[(x - 2)² - 1] = 0

<=> \(\orbr{\orbr{\begin{cases}\left(x-2\right)^6=0\\\left(x-2\right)^2-1=0\end{cases}}}\)

<=> \(\orbr{\begin{cases}x=2\\x=3\end{cases}}\)

Vậy ...

Answer 3

=> x - 2 =0 hoặc x - 2 =1

=> x = 0+2 hoặc x = 1+2

Vậy: x = 2 hoặc x =3