\(x-\dfrac{2}{3}=x+\dfrac{1}{4}\Leftrightarrow0=\dfrac{1}{4}+\dfrac{2}{3}=\dfrac{11}{12}\)vo li
Vay pt vo nghiem
\(\dfrac{x-2}{3}\)=\(\dfrac{x+1}{4}\)
=> (x - 2) . 4 = (x + 1) . 3
=> 4x - 8 = 3x + 3
=> 4x - 3x = 3 + 8
=> x = 11
x- \(\dfrac{2}{3}\) = x+\(\dfrac{1}{4}\)
12. ( x - \(\dfrac{2}{3}\) ) = 12 . ( x + \(\dfrac{1}{4}\) )
4 . (x-2) = 3. (x+1)
4 . x - 8 = 3. |(x+1)|
4 . x - 8=3x + 3
4 . x - 8 = 3 . x + 3 + 8
4 . x = 3 . x + 11
4 . x - 3 . x = 3 . x + 11 - 3 . x
1. x = 3 . x + 11 - 3 . x
x = 3 . x + 11 - 3 . x
VẬY x = 11
y dì
x+14𝑥+14
=> (x - 2) . 4 = (x + 1) . 3
=> 4x - 8 = 3x + 3
=> 4x - 3x = 3 + 8
=> x = 11