Question

(x - 2)(3x + 5) = (2x - 4)(x + 1) giai gium mik dc k

Answer 1

<=>\(3x^2-x-10=2x^2+x-6\)

<=> \(3x^2-x-10-2x^2+2x+6=0\)

<=>\(x^2+x-6=0\)

<=>\(\left(x+3\right)\left(x-2\right)=0\)

<=>\(\orbr{\begin{cases}x+3=0\\x-2=0\end{cases}}\)

<=> \(\orbr{\begin{cases}x=-3\\x=2\end{cases}}\)

Answer 2

(x - 2)(3x + 5) = (2x - 4)(x + 1)

<=>(x - 2)(3x + 5) - (2x - 4)(x + 1) =0

<=>(x - 2)(3x + 5) - 2(x - 2)(x + 1) = 0

<=> ( x - 2)( 3x + 5 - 2x - 2) = 0

<=> (x - 2)( x - 3) = 0

\(\Leftrightarrow\orbr{\begin{cases}x-2=0\\x-3=0\end{cases}\Leftrightarrow\orbr{\begin{cases}x=2\\x=3\end{cases}}}\)

Vậy..........

Answer 3

3x + 5 - 2x - 2 = x - 3???  Sai nhưng đc 3 đúng???