\( {\left( {x - 2} \right)^2} + {\left( {3 - 2x} \right)^2} - \left( {4x - 4} \right)\left( {x - 5} \right) = {\left( {x + 3} \right)^2}\\ \Leftrightarrow {x^2} - 4x + 4 + 9 - 12x + 4{x^2} - 3 - 4{x^2} + 24x - 20 = {x^2} + 6x + 9\\ \Leftrightarrow 8x - 16 = 6x\\ \Leftrightarrow 2x = 16\\ \Leftrightarrow x = 8 \)