\(\left(2x+3\right)^3-\left(x+2\right)^2+\left(x+5\right)\left(x-4\right)=\left(2x-1\right)\left(4x^2+2x+1\right)+18x\left(2x+3\right)\)
\(\Leftrightarrow8x^3+36x^2+54x+27-x^2-4x-4+x^2+x-20=8x^3-1+36x^2+54x\)
\(\Leftrightarrow8x^3+36x^2+51x+3=8x^3+36x^2+54x-1\)
\(\Leftrightarrow-3x=-4\Leftrightarrow x=\dfrac{4}{3}\)
Chúc bạn học tốt !!!!!