Câu 1. Giải các phườn trình sau:
a, 3x+6=0
b, 2x-10=0
c, 3x-7=11
d, 3x-9=0
e, 3x(2-x) =15(x-2)
f, (x+5)(x+4)=0
g, x(x+4)=0
h, (2x -4)(x-2)=0
i, (x+1/5)(2x-3)=0
k, x²-4x=0
m, 4x²-1=0
n, x²-6x+9=0
l, (3x-5)²-(x+4)²=0
o, 7x(x+2)-5(x+2)=0
p, 3x(2x-5)-4x+10=0
q, (2-2x)-x²+1=0
r, x(1-3x)=5(1-3x)
s, 2x-3/4+x+1/6=3
t, x-3/4-2x+1/3=x/6
u, x+1/13+x+2/12=x+3/11+x+4/10
v, 2x+1/15+2x+2/14=2x+3/13+2x+4/12
Giúp e nha mn. E cảm ơn trc ạ!
Phân tích đa thức thành nhân tử
a, (6x+5)2 (3x+2)(x+1) - 35
b, 8(4x+1)(2x-3)(4x-3)(x+1) - 130
c, (4x+1)(2x-1)(3x+2)(x+1) - 4
d, (x+2)(x+3)2(x+4) -12
e, ( x2 +5x+6) (x2 - 15x + 56) -144
g, (x2 - 11x +28) (x2 - 7x + 10) -72
Bài 1: Tìm m để hai phương trình sau tương đương
3mx - 1=5m-x và (2x-1)m=3x-1
Bài 2
a, (14 - 2x)2(3-x)(2x-4)=0
b, (x+3)(2x+3)=4x2-9
c, 8x2=4x
d, x2+4x-5=0
e, x2-5x-14=0
f, x2+3x+3=0
g, 7x2+2x+1=0
h, 3x3+19x2+4x-12=0
Tìm x:
a) 2x (x-5) -(x2-10x +25)=0
b) x2 - 9 +3x(x+3) = 0
c) x3 - 16x = 0
d) (2x+3)(x-2) - (x2 -4x+4) = 0
e) 9x2 -(x2 -2x +1)=0
f)x3-4x2 -9x +36 = 0
g) 3x - 6 = (x-1).(x-2)
i) (x-2).(x+2) +(2x+1)2 =-5x.(x-3) =5
k) x2 -1 = (x-1).(2x+3)
l) (2x-1)2 +(x+3).(x-3) -5x(x-2)=6
d) (5x+3) ( 4x-1) +(10x-7) (-2x+3) =27
e)(8x-5) (3x+2) -(12x+7) (2x-1)=17
f) (5x+9) (6x-1) -(2x-3)( 15z+1) = -190
g) 6x(5x+3) + 3x(1-10x) =7
h) (3x-3) (5 -21x) +(7x+4)(9x-5) =44\
i) (x+1)(x+2)(x-5)-x2 (x+8)=27
Giải các phương trình sau
a) |x-2| = 3
b) |x+1| = |2x+3|
c) |3x| = x+6
d) |x-5| = 13-2x
e) |5x-1| = x-12
f) |-2x| = 3x+4
g) |2x-1| = 6-x
h) |-1+5x| = 8-x
i) |-2x+1| = x+3
k) |-2-5x| = -4x+7
Tìm x
a) x^3 - 16x = 0
b) x^4 - 2x^3 + 10x^2 - 20x = 0
c) (2x - 3 )^2 = (x+5)^2
d) x^2(x-1) - 4x^2 + 8x - 4 = 0
e) x^2 + 4x + 3 = 0
f) x^3 - x^2 = 4x^2 - 8x + 4
g) 2(x+3) - x^2 - 3x = 0
Bµi 5: Gi¶i PT sau.
\(a,\frac{5x-2}{2-2x}+\frac{2x-1}{2}+\frac{x^2+x-3}{1-x}=1\)
b,\(\frac{6x-1}{2-x}+\frac{9x+4}{x+2}=\frac{3x^2-2x+1}{x^2-4}\)
\(c,\frac{1}{x-1}+\frac{2x^2-5}{x^3-1}=\frac{4}{x^2+x+1}\)
d) (x2 + 4x + 8)2 + 3x(x2 + 4x + 8) + 2x2 = 0
e) x4 + 2x3 + 4x2 + 2x + 1 = 0
\(f,\frac{3x-1}{x-1}-\frac{2x+5}{x+3}+\frac{4}{x^2+2x-3}=1\)
Bài 4: Giải các phương trình sau
a) 4(x+5)(x+6)(x+10)(x+12)=\(3x^2\)
b) \(\frac{1}{x^2-3x+3}+\frac{2}{x^2-3x+4}=\frac{6}{x^2-3x+5}\)
c) \(\frac{4x}{4x^2-8x+7}+\frac{3x}{4x^2-10x+7}=1\)
d) \(\dfrac{2x}{2x^2-5x+3}+\dfrac{13x}{2x^2+x+3}=6\)