\(\dfrac{x}{2}=\dfrac{y}{3}\Rightarrow x=\dfrac{2}{3}y\)
Thay vào \(x^2+y^2=325\), ta có:
\(\dfrac{4}{9}y^2+y^2=325\\ \Leftrightarrow\dfrac{13}{9}y^2=325\\ \Leftrightarrow y^2225\\ \Leftrightarrow\left[{}\begin{matrix}y=15\Rightarrow x=10\\y=-15\Rightarrow x=-10\end{matrix}\right.\)
Đặt x/2=y/3=k
=>x=2k; y=3k
x^2+y^2=325
=>13k^2=325
=>k^2=25
TH1: k=5
=>x=10; y=15
TH2: k=-5
=>x=-10; y=-15