#)Giải :
\(x-15=6+4x\)
\(\Leftrightarrow x-15-6+4x=0\)
\(\Leftrightarrow\hept{\begin{cases}x-15=0\\6+4x=0\end{cases}\Leftrightarrow\hept{\begin{cases}x=15\\x=\frac{3}{2}\end{cases}}}\)
Vậy \(x=15;x=\frac{3}{2}\)
\(x-15=6+4x\)
\(\Leftrightarrow x-15=4x+6\)
\(\Leftrightarrow x-15+4x=6\)
\(\Leftrightarrow x-4x-15=6\)
\(\Leftrightarrow-3x=21\Leftrightarrow x=-7\)
x - 15 = 6 + 4x
x - 15 + 4x = 6
x - 4x - 15 = 6
x - 4x = 6 + 15
-3x = 21
x = 21 : (-3)
x = 7