| x + 1 | = 3
\(\Rightarrow\hept{\begin{cases}x+1=3\\x+1=-3\end{cases}\Rightarrow}\hept{\begin{cases}x=2\\x=-4\end{cases}}\)
Vậy .....
\(\left|x+1\right|-1=2\Rightarrow\left|x+1\right|=3\)
\(\Rightarrow\orbr{\begin{cases}x+1=3\\x+1=-3\end{cases}}\Rightarrow\orbr{\begin{cases}x=2\\x=-4\end{cases}}\)
Vậy \(x\in\left\{2;-4\right\}\)
| x + 1 | -1 = 2
<=> | x +1|=2+1=3
<=> x+1=3 hoặc x+1=-3
<=> x=2 hoặc x=-4
ơ......................................
có chắc là toán lp 7 k vậy
à | 2+1| = 3 -1 là = 2 mak
!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
\(\left|x+1\right|-1=2\)\(\Leftrightarrow\left|x+1\right|=3\)
\(\Leftrightarrow\orbr{\begin{cases}x+1=-3\\x+1=3\end{cases}}\Leftrightarrow\orbr{\begin{cases}x=-4\\x=2\end{cases}}\)
Vậy \(x=-4\)hoặc \(x=2\)
\(\left|x+1\right|-1=2\)
\(\Leftrightarrow\left|x+1\right|=2+1=3\)
\(\Leftrightarrow\orbr{\begin{cases}x+1=3\\x+1=-3\end{cases}}\) \(\Leftrightarrow\orbr{\begin{cases}x=2\\x=-4\end{cases}}\)
Vậy x = 2 hoặc x = -4