\(a\left(b+c\right)-d\left(b+c\right)\)
\(=\left(b+c\right)\left(a-d\right)\)
\(ac-ad+bc-bd\)
\(=a\left(c-d\right)+b\left(c-d\right)\)
\(=\left(c-d\right)\left(a+b\right)\)
\(ax+by+bx+ay\)
\(=\left(ax+ay\right)+\left(by+bx\right)\)
\(=a\left(x+y\right)+b\left(y+x\right)\)
\(=\left(x+y\right)\left(a+b\right)\)
ab+ac-do+dc
a(c-d)+b(c-d)
a(x+y)+b(y+x)
Mk làm đúng đó, k mk nha
a(b + c) - d(b + c) = (a - d)(b + c)
ac - ad + bc - bd = a(c - d) + b(c - d) = (a + b)(c - d)
ax + by + bx + ay = (ax + ay) + (by + bx) = a(x + y) + b(x + y) = (a + b)(x + y)