\(\dfrac{77}{78}\) ; \(\dfrac{57}{58}\) ; \(\dfrac{17}{18}\) ; \(\dfrac{7}{8}\)
Ta có : \(\text{1}-\dfrac{7}{8}=\dfrac{\text{1}}{8};\text{1}-\dfrac{\text{1}7}{\text{1}8}=\dfrac{\text{1}}{\text{1}8};\text{1}-\dfrac{57}{58}=\dfrac{\text{1}}{58};\text{1}-\dfrac{77}{78}=\dfrac{\text{1}}{78}\)
Vì \(\dfrac{\text{1}}{8}>\dfrac{\text{1}}{\text{1}8}>\dfrac{\text{1}}{58}>\dfrac{\text{1}}{78}\) nên \(\dfrac{7}{8}< \dfrac{\text{1}7}{\text{1}8}< \dfrac{57}{58}< \dfrac{77}{78}\)
Vậy ta có thứ tự đúng là : \(\dfrac{77}{78};\dfrac{57}{58};\dfrac{\text{1}7}{\text{1}8};\dfrac{7}{8}\)
