Question

viết dưới dạng luỹ thừa   

    \(3^2.\frac{1}{243}.81^2\frac{1}{3^2}\)              \(3^6.256^2.2^4\)

Answer 1

\(3^2.\frac{1}{243}.81^2.\frac{1}{3^2}=\frac{3^2.\left(3^4\right)^2}{3^5.3^2}=\frac{3^2.3^8}{3^7}=3^3\)

\(3^6.256^2.2^4=3^6.\left(2^8\right)^2.2^4=3^6.2^{16}.2^4=3^6.2^{20}\)

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Answer 2

a)\(3^2.\frac{1}{243}.81^2.\frac{1}{3^2}=\frac{3^2.81^2}{243.3^2}=\frac{3^2.\left(3^4\right)^2}{\left(3^5\right).3^2}=\frac{3^2.3^8}{3^5.3^2}=3^3\)

b)\(3^6.256^2.2^4=3^6.\left(2^8\right)^2.2^4=3^6.2^{16}.2^4=3^6.2^{20}\)

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