\(\text{Ư}\left(6\right)=\left\{1;2;3;6\right\}\)
\(\text{Ư}\left(9\right)=\left\{1;3;9\right\}\)
\(\text{Ư}C\left(6;9\right)=\left\{3\right\}\)
a) Ư(6) ={1;2;3;6} Ư(9)= {1;3;9} ƯC(6,9) ={1;3}
b) Ư(7) ={1;7} Ư(8) = {1;2;4;8} ƯC(7,8) = {1}
c) ƯC(4;6;8)={1;2}
k mik nha
a) Ư (6) = {1; 2; 3; 6}, Ư (9) = {1, 3, 9}, ƯC (6, 9) = {1; 3}.
b) Ư (7) = {1; 7}, Ư (8) = {1; 2; 4; 8}, ƯC (7, 8) = {1}.
c) ƯC (4, 6, 8) = {1, 2}.
a) Ư(6) = { 1 ; 2 ; 3 ; 6 }
Ư(9) = { 1 ; 3 ; 9 }
=> ƯC( 6;9 ) = { 1 ; 3 }
b) Ư(7) = { 1 ; 7 }
Ư( 8) = { 1 ; 2 ; 4 ; 8 }
ƯC(7;8) = { 1 }
c) ƯC ( 4;6;8 ) = { 1 ; 2 }