a) 0,32 = \(\frac{32}{100}=\frac{2^5}{10^2}=\frac{2^5}{\left(2.5\right)^2}=\frac{2^3}{5^2}=\frac{8}{25}\)
b) -0,124 = \(\frac{124}{1000}=\frac{-31.4}{10^3}=\frac{-31.2^2}{2^3.5^3}=\frac{-31}{2.5^3}=\frac{-31}{250}\)
c) 1,28 = \(\frac{32}{25}\)
d) -3,12 = \(\frac{-78}{25}\)
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a) \(0,32=\) \(\frac{32}{10}=\frac{16}{5}\)
b) \(-0,124=-\frac{124}{1000}=-\frac{31}{250}\)
c) \(1,28=\frac{128}{100}=\frac{32}{25}\)
d) \(-3,12=-\frac{312}{100}=-\frac{78}{25}\)
nha bn
\(a,\)\(0,32=\frac{8}{25}\)
\(b,\)\(-0,124=-\frac{31}{250}\)
\(c,\)\(1,28=\frac{32}{25}\)
\(d,\)\(-3,12=-\frac{78}{25}\)
viết các số sau đây thành phân số tối giản :
a) 0,32
= \(\frac{32}{100}=\frac{8}{25}\)
b) -0,124
= \(\frac{-124}{1000}=\frac{-31}{250}\)
c) 1,28
= \(\frac{128}{100}=\frac{32}{35}\)
d) -3,12
= \(\frac{-312}{100}=\frac{-78}{25}\)