theo thu tu tu be den lon la 6/20 ; 12/32 ; 9/12 . Duyet di nhe
\(\frac{6}{20}=\frac{3}{10}\)
\(\frac{9}{12}=\frac{3}{4}\)
\(\frac{12}{32}=\frac{3}{8}\)
\(\Rightarrow\frac{3}{10}<\frac{3}{8}<\frac{3}{4}\) hay \(\frac{6}{20}<\frac{12}{32}<\frac{9}{12}\)
\(\frac{6}{20}=\frac{3}{10}\)
\(\frac{9}{12}=\frac{3}{4}\) Vì \(\frac{3}{4}>\frac{3}{8}>\frac{3}{10}\)
\(\frac{12}{32}=\frac{3}{8}\) Nên \(\frac{6}{20}<\frac{12}{32}<\frac{9}{12}\)
\(\frac{6}{20}<\frac{12}{32}<\frac{9}{12}\)