Gọi 3 số cần tìm là a,b,c. Theo đài đề bài ta có :
\(\left(a+b+c\right):3=6\)\(\Rightarrow a+b+c=18\)\(\left(1\right)\)
\(\left(2a+b+c\right)=8\Rightarrow2a+b+c=24\)\(\left(2\right)\)
\(\left(a+b+9c\right):3=30\Rightarrow a+b+9c=90\)
Lấy \(\left(2\right)-\left(1\right)\)Ta có :
\(2a+b+c-a-b-c=24-18\)
\(a=6\)mà \(a+b+c=18\Rightarrow b+c=12\Rightarrow c=12-b\)
\(a+b+9c=90\)
\(6+b+9\left(12-b\right)=90\)
\(6+b+108-9b=90\)
\(114-8b=90\)
\(8b=114-90=24\Rightarrow b=24:8=3\)
\(a+b+c=18\)
\(6+3+c=18\)
\(c=18-6-3=9\)
Vậy a= 6
b= 3
c= 9