a, \(\dfrac{5}{\sqrt{7}}=\dfrac{5\sqrt{7}}{7}\)
b, \(\dfrac{3}{\sqrt{3}+7}=\dfrac{3\left(7-\sqrt{3}\right)}{46}\)
c, \(\dfrac{1}{\sqrt{2}+\sqrt{3}}=\dfrac{\sqrt{3}-\sqrt{2}}{1}=\sqrt{3}-\sqrt{2}\)
d, \(\dfrac{37}{7-2\sqrt{3}}=\dfrac{37\left(7+2\sqrt{3}\right)}{37}=7+2\sqrt{3}\)