\(-\frac35;\frac57;-\frac79;-\frac{9}{11};\frac{11}{13}\)
ta có \(-\frac35;-\frac79;-\frac{9}{11}\) >0
\(\frac57;\frac{11}{13}\) <0
=>\(-\frac35;-\frac79;-\frac{9}{11}\) >\(\frac57;\frac{11}{13}\)
\(\frac{279}{495}<\frac{385}{495}<\frac{405}{495}\) hay\(\frac35<\frac79<\frac{9}{11}\) suy ra \(-\frac35>-\frac79>-\frac{9}{11}\)
vậy \(-\frac{9}{11}\)