\(B=1.2+2.3+3.4+4.5+....+99.100\)
\(3B=1.2.3+2.3.\left(4-1\right)+3.4.\left(5-2\right)+...+99.100.\left(101-98\right)\)
\(3B=1.2.3+2.3.4-1.2.3+3.4.5-2.3.4+....+99.100.101-98.99.100\)
\(3B=99.100.101\)
\(B=\frac{99.100.101}{3}=\frac{999900}{3}=333300\)