Ta có : \(S=\frac{4}{5.7}+\frac{4}{7.9}+...+\frac{4}{59.61}\)
\(=\frac{2}{5}-\frac{2}{7}+\frac{2}{7}-\frac{2}{9}+...+\frac{2}{59}-\frac{2}{61}\)
\(=\frac{2}{5}-\frac{2}{61}=\frac{122-10}{305}=\frac{112}{305}\)
Ta có : \(S=\frac{4}{5.7}+\frac{4}{7.9}+...+\frac{4}{59.61}\)
\(=\frac{2}{5}-\frac{2}{7}+\frac{2}{7}-\frac{2}{9}+...+\frac{2}{59}-\frac{2}{61}\)
\(=\frac{2}{5}-\frac{2}{61}=\frac{122-10}{305}=\frac{112}{305}\)
Tính\(\frac{4}{5.7}+\frac{4}{7.9}+...+\frac{4}{59.61}\)
\(B=\frac{4}{5.7}+\frac{4}{7.9}+......+\frac{4}{59.61}\) = ?
Help me do my homework
\(\frac{4}{5.7}+\frac{4}{7.9}+....+\frac{4}{59.61}\)
Tính nhanh giá trị biểu thức sau :
\(\frac{4}{5.7}\)+ \(\frac{4}{7.9}\)+ ...+ \(\frac{4}{59.61}\)
bài 1 tính
A = \(\frac{2}{3.5}+\frac{2}{5.7}+..............+\frac{2}{37.39}\); B = \(\frac{4}{5.7}+\frac{4}{7.9}+..........+\frac{4}{59.61}\) ; C = \(\frac{4}{5.9}+\frac{4}{9.13}+.................+\frac{4}{41.45}\) Bài 2 chứng minh : \(\frac{m}{b.\left(b+m\right)}=\frac{1}{b}-\frac{1}{b+m}\)
tính tổng S=\(\frac{2}{5.7}+\frac{2}{7.9}+...+\frac{2}{59.61}\)
Tính giá trị các biểu thức sau bằng phương pháp hợp lí
a) \(\frac{4}{5.7}+\frac{4}{7.9}+...+\frac{4}{59.61}\)
b) \(\frac{24.47-23}{24+47.23}.\frac{3+\frac{3}{7}-\frac{3}{11}+\frac{3}{1001}-\frac{3}{13}}{\frac{9}{1001}-\frac{9}{13}+\frac{9}{7}-\frac{9}{11}+9}\)
1. Tính tích
\(A=\frac{3}{4}.\frac{8}{9}.\frac{15}{16}....\frac{899}{900}\)
2 Chứng tỏ rằng:\(y=\frac{1}{5}+\frac{1}{6}+\frac{1}{7}+...+\frac{1}{17}<2\)
3. tính nhanh \(y=\frac{3}{5.7}+\frac{3}{7.9}+...+\frac{3}{59.61}\)
4. Chứng minh rằng \(S=\frac{1}{2}+\frac{1}{2^2}+\frac{1}{2^3}+...+\frac{1}{2^{20}}<1\)
Tính hợp lý : \(M=\frac{3}{5.7}+\frac{3}{7.9}+...+\frac{3}{59.61}\)