Các câu hỏi tương tự
Tính tổng
M = \(\left(1-\frac{1}{1-2010}\right)\left(2-\frac{1}{1-\frac{2010}{2}}\right)\left(3-\frac{1}{1-\frac{2010}{3}}\right)....\left(5000-\frac{1}{1-\frac{5000}{3}}\right)\)
\(\frac{\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+....+\frac{1}{2011}}{\frac{2010}{1}+\frac{2009}{2}+\frac{2008}{3}+....+\frac{1}{2010}}\)
Rút gọn:
\(F=\frac{\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+.......+\frac{1}{2012}}{\frac{2011}{1}+\frac{2010}{2}+........+\frac{2}{2010}+\frac{1}{2011}}\)
H = \(\frac{\frac{2010}{1}+\frac{2009}{2}+...+\frac{3}{2008}+\frac{2}{2009}+\frac{1}{2010}}{\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+...+\frac{1}{2011}}\) =?
\(\frac{\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+....+\frac{1}{2011}}{\frac{2010}{1}+\frac{2009}{2}+\frac{2008}{3}+....+\frac{1}{2010}}\)
\(\frac{\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+....+\frac{1}{2011}}{\frac{2010}{1}+\frac{2009}{2}+\frac{2008}{3}+....+\frac{1}{2010}}\)
giup minh voi
Tinh\(\frac{x-1}{2010}+\frac{x-2}{2009}+.....+\frac{x-2010}{1}=2010\)
Tính \(A=-\frac{1}{2010}-\frac{1}{2010\times2009}-\frac{1}{2009\times2008}-.....-\frac{1}{3\times2}-\frac{1}{2\times1}\)
A = \(1-\frac{1}{2^2}-\frac{1}{3^2}-\frac{1}{4^2}-...-\frac{1}{2010^2}\)
Chứng minh rằng : A > \(\frac{1}{2010}\)