Trả lời:
\(\frac{4}{\sqrt{7}-\sqrt{3}}+\frac{6}{3+\sqrt{3}}+\frac{\sqrt{7}-7}{\sqrt{7}-1}\)
\(=\frac{4.\left(\sqrt{7}+\sqrt{3}\right)}{7-3}+\frac{6.\left(3-\sqrt{3}\right)}{9-3}-\frac{7-\sqrt{7}}{\sqrt{7}-1}\)
\(=\frac{4.\left(\sqrt{7}+\sqrt{3}\right)}{4}+\frac{6.\left(3-\sqrt{3}\right)}{6}-\frac{\sqrt{7}.\left(\sqrt{7}-1\right)}{\sqrt{7}-1}\)
\(=\sqrt{7}+\sqrt{3}+3-\sqrt{3}-\sqrt{7}\)
\(=3\)
Học tốt