\(\frac{12^3+3.12^2+3^3}{162}\)
\(=\frac{2^4.3^2+3^3.2^4+3^3}{2.3^4}\)
\(=\frac{3^2.\left(2^4+3.2^4+3\right)}{2.3^4}\)
\(=\frac{2^4+3.2^4+3}{2.3^2}=\frac{16+3.16+3}{2.9}\)
\(=\frac{67}{18}\)
\(\frac{12^3+3.12^2+3^3}{162}=\frac{2^6.3^3+3^3.2^4+3^3}{2.3^4}=\frac{3^3\left(2^6+2^4+1\right)}{2.3^4}\)
\(=\frac{2^6+2^4+1}{2.3}=\frac{64+16+1}{6}=\frac{81}{6}=\frac{27}{2}=13,5\)