a) Ta có: \(\left(1-\frac{1}{3}\right).\left(1-\frac{1}{4}\right).\left(1-\frac{1}{5}\right)=\frac{2}{3}.\frac{3}{4}.\frac{4}{5}=\frac{2.3.4}{3.4.5}=\frac{2}{5}.\)
b) Ta có: \(\left(1+\frac{1}{3}\right).\left(1+\frac{1}{4}\right).\left(1+\frac{1}{5}\right)=\frac{4}{3}.\frac{5}{4}.\frac{6}{5}=\frac{4.5.6}{3.4.5}=\frac{6}{3}=2\)
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