\(a,\sqrt{68^2-32^2}\)
\(=\sqrt{\left(68-32\right)\left(68+32\right)}\)
\(=\sqrt{3600}=60\)
\(b,\sqrt{37^2-12^2}\)
\(=\sqrt{\left(37-12\right)\left(37+12\right)}\)
\(=\sqrt{25.49}=5.7=35\)
\(c,\sqrt{21,8^2-18,2^2}\)
\(=\sqrt{\left(21,8+18,2\right)\left(21,8-18,2\right)}\)
\(=\sqrt{40.3,6}=12\)
1) Tính
a) \(\dfrac{1}{2-\sqrt{3}}\)-3\(\sqrt{\dfrac{1}{3}}\)\(+\sqrt{12}\)
b) \(\dfrac{2}{1+\sqrt{2}}-\sqrt{9-\sqrt{32}}\)
tính
A=\(\left(1-\sqrt{7}\right).\dfrac{\sqrt{7}+7}{2\sqrt{7}}\)
B=\(3\sqrt{3}+4\sqrt{12}-5\sqrt{27}\)
C=\(\sqrt{32}-\sqrt{50}+\sqrt{18}\)
D=\(\sqrt{72}+\sqrt{4\dfrac{1}{2}}-\sqrt{32}-\sqrt{162}\)
E=\(\dfrac{1}{2}\sqrt{48}-2\sqrt{75}-\dfrac{\sqrt{33}}{\sqrt{11}}+5\sqrt{1\dfrac{1}{3}}\)
Bài 1: thực hiện phép tính
a) \(\sqrt{252}-\sqrt{700}+\sqrt{1008}-\sqrt{448}\)
Bài 2: Tính
a) \(\dfrac{\sqrt{99999}}{\sqrt{11111}}\)
b) \(\dfrac{\sqrt[]{84^2-37^2}}{\sqrt[]{47}}\)
c) \(\sqrt{\dfrac{5\left(38^2-17^2\right)}{8\left(47^2-19^2\right)}}\)
d) \(\dfrac{\sqrt{0,2.1,21.0,3}}{\sqrt{7,5.3,2.0,64}}\)
Bài 3: Tính (viết dưới dạng tích dưới dấu căn bậc hai)
a) \(\sqrt{27^2-23^2}\)
b) \(\sqrt{37^2-35^2}\)
c)\(\sqrt{65^2-63^2}\)
d) \(\sqrt{117^2-108^2}\)
\(\frac{\sqrt{12,5}}{\sqrt{0,5}}\)
\(\frac{\sqrt{6}}{\sqrt{150}}\)
\(\sqrt{6,8^2-3,2^2}\)
\(\sqrt{21,8^2-18,2^2}\)
6) Thực hiện các phép tính
a. \(\sqrt{2}\left(\sqrt{8}+\sqrt{32}-\sqrt{98}\right)\)
b. \(\dfrac{2}{\sqrt{5}+2}+\dfrac{2}{2-\sqrt{5}}\)
c. \(\left(2+\sqrt{3}\right)\sqrt{11-6\sqrt{2}}\)
Mng giúp mik vs ạ >.<!!
Tính
a,8+2\(\sqrt{15}\)
b,12+2\(\sqrt{35}\)
c,8+\(\sqrt{60}\)
Tính
a,\(\sqrt{4+\sqrt{15}}\)
b,\(\left(3-\sqrt{2}\right)\sqrt{11+6\sqrt{2}}\)
c,\(\left(\sqrt{5}+\sqrt{7}\right)\sqrt{12-2\sqrt{35}}\)
Tính
A= \(\sqrt{\left(1-\sqrt{3}\right)^2}-\sqrt{\left(\sqrt{3}+2\right)^2}\)
B=\(\sqrt{\left(2-\sqrt{3}\right)^2}+\sqrt{4-2\sqrt{3}}\)
C=\(\sqrt{15-6\sqrt{6}}+\sqrt{33-12\sqrt{6}}\)
* Thực hiện phép tính
a, A= \(\sqrt{12-3\sqrt{7}}-\sqrt{12+3\sqrt{7}}\)
b, B= \(\sqrt{4+\sqrt{10+2\sqrt{5}}}+\sqrt{4-\sqrt{10+2\sqrt{5}}}\)
c, C= \(\sqrt{3-\sqrt{5}}+\sqrt{3+\sqrt{5}}\)
