Question

tính:

\(A=\left[\left(\frac{2}{193}-\frac{3}{386}\right).\frac{193}{17}+\frac{33}{34}\right]:\left[\left(\frac{7}{1931}+\frac{11}{3862}\right).\frac{1931}{25}+\frac{9}{2}\right]\)

Answer 1

Khó nhỉ

Answer 2

\(A=\left[\left(\frac{2}{193}-\frac{3}{386}\right).\frac{193}{17}+\frac{33}{34}\right]\div\left[\left(\frac{7}{1931}+\frac{11}{3862}\right).\frac{1931}{25}+\frac{9}{2}\right]\)     

    \(=\left[\left(\frac{4}{386}-\frac{3}{386}\right).\frac{193}{17}+\frac{33}{34}\right]\div\left[\left(\frac{14}{3862}+\frac{11}{3862}\right).\frac{1931}{25}+\frac{9}{2}\right]\)

    \(=\left[\frac{1}{386}.\frac{193}{17}+\frac{33}{34}\right]\div\left[\frac{25}{3862}.\frac{1931}{25}+\frac{9}{2}\right]\) 

    \(=\left[\frac{1}{34}+\frac{33}{34}\right]\div\left[\frac{1}{2}+\frac{9}{2}\right]\)

    \(=1\div5=0,2\)

Vậy A = 0,2