Các câu hỏi tương tự
so sánh\(A=\frac{31}{13}-\left(\frac{7}{32}+\frac{8}{2}\right)vaB=\left(\frac{1}{3}+\frac{12}{67}+\frac{13}{41}\right)-\left(\frac{79}{67}-\frac{28}{41}\right)\)
\(\frac{31}{23}-\left(\frac{7}{32}+\frac{8}{23}\right)+\left(\frac{1}{3}+\frac{12}{67}+\frac{13}{41}\right)-\left(\frac{79}{67}-\frac{28}{41}\right)\)
\(\left(\frac{1}{3}+\frac{12}{67}+\frac{13}{41}\right)-\left(\frac{79}{67}-\frac{28}{41}\right)\)
Tính
\(\left(\frac{1}{3}+\frac{12}{67}+\frac{13}{41}\right)-\left(\frac{79}{67}-\frac{28}{41}\right)\)
So sánh : A = \(\frac{31}{23}+\left(\frac{7}{23}+\frac{8}{2}\right)\)và B = \(\left(\frac{1}{3}+\frac{12}{67}+\frac{13}{41}\right)-\left(\frac{79}{67}+\frac{28}{41}\right)\)
\(\left(\frac{1}{3}+\frac{12}{67}+\frac{13}{41}\right)-\frac{79}{67}+\frac{28}{41}\)
so sánh: A= \(\frac{31}{23}-\left[\frac{7}{32}+\frac{8}{2}\right]\) và B=\(\left[\frac{1}{3}+\frac{12}{67}+\frac{13}{41}\right]-\left[\frac{79}{67}-\frac{28}{41}\right]\)
So sánh:
A = \(\frac{31}{23}-\left(\frac{7}{32}+\frac{8}{2}\right)\)và B = \(\left(\frac{1}{3}+\frac{12}{67}+\frac{13}{41}\right)-\left(\frac{79}{67}-\frac{28}{41}\right)\)
1) Tính hợp lýa)frac{31}{23}-left(frac{7}{32}+frac{8}{32}right)b)left(frac{1}{3}+frac{12}{67}+frac{13}{41}right)-left(frac{79}{67}-frac{28}{41}right)c)frac{38}{45}-left(frac{8}{45}-frac{17}{51}-frac{3}{11}right)d)left(frac{17}{28}+frac{18}{29}-frac{19}{30}-frac{30}{31}right).left(-frac{5}{12}+frac{1}{4}+frac{1}{6}right)
Đọc tiếp
1) Tính hợp lý
a)\(\frac{31}{23}-\left(\frac{7}{32}+\frac{8}{32}\right)\)
b)\(\left(\frac{1}{3}+\frac{12}{67}+\frac{13}{41}\right)-\left(\frac{79}{67}-\frac{28}{41}\right)\)
c)\(\frac{38}{45}-\left(\frac{8}{45}-\frac{17}{51}-\frac{3}{11}\right)\)
d)\(\left(\frac{17}{28}+\frac{18}{29}-\frac{19}{30}-\frac{30}{31}\right).\left(-\frac{5}{12}+\frac{1}{4}+\frac{1}{6}\right)\)