a,\(\frac{7}{8}+\frac{3}{5}=\frac{35}{40}+\frac{24}{40}=\frac{35+24}{40}=\frac{59}{40}\)
b, \(\frac{20}{24}:\frac{5}{8}=\frac{20}{24}x\frac{8}{5}=\frac{20x8}{24x5}=\frac{160}{120}=\frac{4}{3}\)
c,\(\frac{8}{3}-\frac{2}{5}x\frac{1}{6}=\frac{8}{3}-\frac{2x1}{5x6}=\frac{8}{3}-\frac{1}{15}=\frac{13}{5}\)
a) 7/8 + 3/5 = 59/40
b) 20/24 : 5/8 = 4/3
c) 8/3 - 2/5 x 1/6 = 8/3 - 1/15 = 13/5
7/8+3/5=35/40+24/40=59/40
20/24:5/8=160/120
8/3-2/*1/6=8/3-2/30=80/30-2/30=78/30
a, \(\frac{7}{8}\)+\(\frac{3}{5}\)= \(\frac{7\cdot5}{40}\)+ \(\frac{3\cdot8}{40}\)= \(\frac{35}{40}\)+\(\frac{24}{40}\)= \(\frac{59}{40}\)
b, \(\frac{20}{24}\): \(\frac{5}{8}\)= \(\frac{20}{24}\)* \(\frac{8}{5}\)= \(\frac{4}{3}\)*\(\frac{1}{1}\)= \(\frac{4}{3}\)
c,\(\frac{8}{3}\)- \(\frac{2}{5}\)* \(\frac{1}{6}\)= \(\frac{8}{3}\)- \(\frac{1}{15}\)= \(\frac{8\cdot5}{15}\)- \(\frac{1}{15}\)= \(\frac{40}{15}\)- \(\frac{1}{15}\)= \(\frac{13}{5}\)
