Ta có : \(A=\frac{11.3^{22}.3^7-9^{15}}{\left(2.3^{14}\right)^2}\)
\(\Rightarrow\) \(A=\frac{11.3^{22+7}-\left(3^2\right)^{15}}{2^2.\left(3^{14}\right)^2}\)
\(\Rightarrow\) \(A=\frac{11.3^{29}-3^{30}}{2^2.3^{28}}\)
\(\Rightarrow\) \(A=\frac{3^{29}.\left(11-3\right)}{2^2.3^{28}}\)
\(\Rightarrow\) \(A=\frac{3^{29}.8}{2^2.3^{28}}\)
\(\Rightarrow\) \(A=\frac{3^{29}.2^3}{2^2.3^{28}}\)
\(\Rightarrow\) \(A=3.2\)
\(\Rightarrow\) \(A=6\)
Vậy A = 6
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