[92-1/9-2/10-3/11-....-92/100]:[1/45+1/50+1/55+....1/500]
92-1/9-2/10-3/11-....-92/100
------------------------------------
1/45+1/50+1/55+......+1/500
[92--1/9-2/10-3/11-4/12-92/100] :[1/45+1/50+1/55+1/60+1/500]
TÍNH :
[ 92 -1/9-2/10-3/11-.....-92/100] : [1/45+1/50+1/55+....+1/500]
làm hộ mk nhá, thanks
Tính : \(\left(92-\frac{1}{9}-\frac{2}{10}-\frac{3}{11}-...-\frac{92}{100}\right)\) \(\div\left(\frac{1}{45}+\frac{1}{50}+\frac{1}{55}+...+\frac{1}{500}\right)\)
Tính: \(S=\frac{92-\frac{1}{9}-\frac{2}{10}-\frac{3}{11}-....-\frac{90}{98}-\frac{91}{99}-\frac{92}{100}}{\frac{1}{45}+\frac{1}{50}+\frac{1}{55}+....+\frac{1}{495}+\frac{1}{500}}\)
Giúp mình nha! ^_^
(\(92-\frac{1}{9}-\frac{2}{10}-\frac{3}{11}-........-\frac{92}{100}\))\(\cdot x=\)(\(\frac{1}{45}+\frac{1}{51}+\frac{1}{55}+........+\frac{1}{500}\))
Tính:
\(\left(92-\frac{1}{9}-\frac{2}{10}-\frac{3}{10}-.-\frac{92}{100}\right):\left(\frac{1}{45}+\frac{1}{50}+\frac{1}{55}+.+\frac{1}{500}\right)\)
dấu\(.\)nghĩa là dấu 3 chấm nhé! ai xong và đúng sẽ có tích.
Tính: \(S=\frac{92-\frac{1}{9}-\frac{2}{10}-\frac{3}{11}-.....-\frac{90}{98}-\frac{91}{99}-\frac{92}{100}}{\frac{1}{45}+\frac{1}{50}+\frac{1}{55}+.....+\frac{1}{495}+\frac{1}{500}}\)
Giúp mình nha! Cảm ơn nhiều! ^_^